Question

Construct the right angled ∆pqr where m < Q = 90 degree QR = 7 cm and PR = 9 cm

Answer 1

Answer:

STEPS OF CONSTRUCTION :

1. draw line segment QR of length 7cm
2. construct an angle of 90° from point Q. (take any radius in your compass and construct 60° and 120° ans bisect it.)
3. extend the line drawn.
4. take 9cm radius in a compass and cut an arc on the so formed line.
5. marks point P
6. join PR.
7. thus, PQR is the required triangle.

hope this helps you!