Math, asked by aakanshasinghbaghel, 2 months ago

construct the right angled ∆PQR where M <Q=90°QR=8cm and PR=10cm​

Answers

Answered by rk988929
1

Answer:

First draw a line segment QR=8cm, then on point Q draw an angle of 90°. Now from point R mark an arc of 10cm and name the point as P. Join Q and P.

Thus, ∆PQR is the required right angle triangle

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