Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.
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Step-by-step explanation:
1. Take a linesegment 8 CM QR.
2. Draw 90 degrees with compass on Q and draw an arc 10cm frm p it joins on the line 90 degrees
3. Add rp which is 10cm
hence PQR Is the required triangle
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