Question

Construct the square root of spiral

Answer 1

hope this helps you........

Answer 2

1) Construct an isosceles right triangle ABC with side 1 inch. (You can use the corner of an index card to make sure you are constructing a perfect right angle.) The hypotenuse AC will then by equal to the square root of 2.

2) Construct line at point C perpendicular to segment AC. Construct segment CD on this new line, equal in length to segment AB. Construct segment CD on this new line, equal in length to segment AB. Connect points A and C. Construct a line at C perpendicular to AC. Construct segment CD equal in length to segment AB or BC. Then construct segment AD. AD will then be equal to the square root of 3 (use the Pythagorean Theorem to calculate this length).You now have 2 right triangles, with one leg of the second triangle formed by the hypotenuse of the first triangle. You now have two right triangles, as shown below:

3) Construct a line at C perpendicular to AC. Construct segment CD equal in length to segment AB or BC. Then construct segment AD. AD will then be equal to the square root of 3 (use the Pythagorean Theorem to calculate this length). Construct a line at D perpendicular to AD. Construct segment CD equal in length to segment AB or BC. Then construct segment AD. AD will then be equal to the square root of 3 (use the Pythagorean Theorem to calculate this length).You now have two right triangles, as shown below:

4) Continue this process until you have 11 right triangles as shown below. If you have used a compass and straightedge, trace the segments onto a clean sheet of paper, without the construction marks.