Question

construct the triangle ABC such that BC = 6 cm , angleB =45 degree and angleA = 75 degree

Answer 1

Answer:

Steps of Construction :

1. Draw a line segment BC=6 cm

2. Make an angle PCB = 45

∘

with the help of a protractor

3. Draw the perpendicular bisector RQ of AB

4. Draw BE⊥BP at B

Let RQ and BE intersect at O

5. Draw the circle with centre O and radius OB

Then any angle in the major segment = ∠PBC=45

∘

6. Let RQ intersect BC to D is the mid-point of BC. Taking D as centre and 5 cm radius draw arcs intersecting the circle in A,A

′

.

7. Join AB,AC and A

′

B,A

′

C

Then the required triangle is ABC or A

′

BC.