Question

construct the triangle per given pq=4cm angle q=70degree qr=4.5cm​

Answer 1

Answer:

Construction steps :

1 ) Draw a line segment PB = 4cm

2 ) Construct a ray QX such that

<PQX = 60°

3 ) Take Q as a center with radius 4.5cm

draw an arc which cuts QX at R .

4 ) Join R to P .

Required ∆PQR formed.