Question

construct the triangle Showdow similar to the
given AABC, with its sides equal to 5/3 of
the corresponding sides of the AABc​

Answer 1

Given, a ΔABC, we are required to construct a triangle whose side are of the corresponding sides of Δ ABC

the Steps are :-

1) Draw any ray BX making an acute angel with BC on the sides opposite to the vertex A.

2) Locate the points on BX such that

3) Join to C as 3 being smaller and through draw a line parallel to , intersecting the extended line segment BC at C’.

4) Draw a line through C parallel to CA intersecting the extended line segment BA at A’.

Then A’BC’ is the required triangle.

hope it help