Math, asked by Priyanka2003, 1 year ago

construct this quadrilateral Abcd in which
1) AB=4.5 cm , BC=3.8 cm , angleBCD=90 degree , angleBAD=60degree & angle 120 degree.
2) angle b =45 degree, angle C =90 degree, Bc = 5 cm ,Ab = 4 cm and cd = 3 cm


yakumoreyucurry: In (1), which angle is supposed to be 120 degree?
Priyanka2003: angle abc = 120 degree

Answers

Answered by yakumoreyucurry
6
Steps of construction for 1:-
1. Draw the line BC.
2. On the point B, make angle 120° and draw a line passing through it.
3. Take 4.5 cm on the compass and from point B, cut an arc on the line and mark the point of intersection as point A.
4. On the point A, make angle 60° and draw a line passing through it.
5. On the point C, make angle 90° and draw a line passing through it.
6. Mark the point of intersection of the two lines as point D.

Steps of construction for 2:-
1. Draw the line BC
2. On the point B, make angle 45° and draw a line passing through it.
3. Take 4 cm on the compass and from point B, draw an arc on the line and mark the point of intersection as point A.
4. On the point C, make angle 90° and draw a line passing through it.
5. Take 3 cm on the compass and from point C, draw an arc on the line and mark the point of intersection as point D.
6. Join A and D.
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yakumoreyucurry: Please mark this answer as Brainliest.
Priyanka2003: Yes...thank you very much
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