Question

Construct triangle ABC
AB=7 cm
BC=8 cm
ANGLE ABC=60°
Locate by construction the point the point P such that
1) P is equidistant from B&C
2)P is equidistant from AB&PB
3)Measures and record the length of PB

Answer 1

Follow these steps to construct our diagram from given information , As :

Step 1  : Draw a line AB =   7  cm

Step 2 : Take any radius ( Less than half of line AB )  and center " B "  draw an arc that intersect our line AB at  " X " . With same radius and center " X "  draw another arc that intersect our previous arc at  "Y " .

Step 3 :  Join BY and extend that line to Z , we get BZ  .

Step 4 : Take radius of 8 cm and center " B "  draw an arc that intersect our line BZ at  " C " .  Join AC we get required triangle ABC .

Step 5 : Take any radius ( More than half of line BC )  and take center B and C draw two arcs these arcs intersect at  " P "  . This point P is equidistance from B and C .

But we can't draw point  " P " that is equidistance from AB and PB ( As given in second query ) So Kindly recheck that and get back to us , So we can help you precisely  .

Answer 2

the ratio between two numbers 5 : 9 find the number is there a HCF is 16what is the answer of it not construction of trianglethe ratio between two numbers 5 to 9 find the number if the HCF is 16