Question

Construct triangle ABC if AB+BC+AC = 12cm and angle A = 90°, angle B = 60°​

Answer 1

Answer:

In ∆ ABC , angle B=90° , angle C= 60° , angle A=30° and BC=12 cm. , applying

sine rule:-

AB/sinC = BC/sinA = CA/sinB.

or. AB/sin60° = 12/sin30°= CA/sin90°.

or. 2.AB/√3. = 2.12/1= CA/1.

or. AB = 12√3 cm. , CA(hypotenuse) = 24cm.

Area of triangle ABC = (1/2)×AB×BC = (1/2)× 12√3×12

= 72√3 cm^2. = 124.704 cm^2.