Question

construct triangle ABC in which AB = 5 cm,BC = 6cm and CA = 5.5cm

only steps of construction needed​

Answer 1

Answer:

Steps of Construction :

(1) Draw a line AB = 6 cm.

(2) Using compass, taking A and B as centre draw arcs of 5 cm and 5.6 cm respectively, which cut each other at C.

(3) Join AC and BC.

(4) Now, from vertex A draw a bisector AD towards BC.

On measuring length AD = 5 cm.

Explanation:

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Answer 2

Answer:

Steps of construction:

1) Draw a line segment AB of length 5.5cm.

2) From B, cut an arc of radius 6cm.

3) With centre A, draw an arc of radius 7cm intersecting the previously drawn arc at say, C.

4) Join AC and BC to obtain the desired triangle.

5) With centre B and radius more than half of

BC, draw two arcs on both sides of BC.

6) With centre C and the same radius as in the previous step, draw two arcs intersecting the arcs drawn in the previous step at X and Y.

9) Join XY to get the perpendicular bisector of BC.

Explanation:

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