Construct Triangle ABC in which base BC = 3cm, Angle B = 30 degree and AB + AC = 5.2cm
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construct a triangle ABC in which base BC is equal to 3 cm and angle b is ... Step I: Draw the line segment BC = 3 cm and at point B, make an angle of 30°, say ∠XBC. Step II: Cut the line segment BD = 5.2 cm (equal to AB + AC) on ray BX. Step III: Join DC and draw the perpendicular bisector PQ of DC. Step IV: Let it intersect BX at point A.
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