Construct triangle ABC in which BC=3.2 cm angle ACB=45° and perimeter of triangle is 10 cm
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Answer:
Given : triangle ABC, in which BC=3.2 cm angle ACB=45° and perimeter of triangle ABC is 10 cm
To find : Construct triangle
Solution :
Step 1: Draw a line segment BC 3.2 cm.
Step 2: Draw ZC = 45° using protractor and draw a ray CX.
Step 3: With Center C and radius 10-3.2= 6.8 cm, make an arc which intersects CX at D.
Step 4: Join BD
Step 5: Draw a perpendicular bisector of segment DB it intersect the ray CX at point A.
Step 6: Join C to B
Triangle is constructed.
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