Question

construct triangle ABC in which BC=3.6cm , AB+AC=4.8cm and angle b=30

Answer 1

steps of construction:
(1) construct a line line segment bc of length 3.6 CM
(2) construct a 30 degree angle at b
(3) take C the centre and 4.8 CM radii draw an Arc
(4) construct a line from be such that AB + AC is equals to 4.8 CM

Answer 2

Steps of construction:

1. Draw a line segment BC of 3.6cm.

2. At the point B, draw ∠x BC  of 60o

3. With center B and radius 4.8cm, draw an arc which intersects XB at D.

4. Join DC

5. Draw the perpendicular bisector of DC which intersects DB at A.

6. Join AC

Hence  Δ  ABCis the required triangle