Question

construct triangle ABC in which BC=4.2cm, angle B=30 degree and AB-AC=1.6cm

Answer 1

Triangle ABC,

BC = 4.2 cm,

angle B = 30°,

AB - AC =1,

we have to construct the Triangle ABC,

steps of construction :----

1), We draw BC = 4.2 cm as base of triangle,

2) At the point B , we draw a 30° angle,

3)Let's cut the line segment BD equal to AB - AC =1.6 cm, from the ray BX,

4)now we join DC,

5)Draw the perpendicular bisector PQ of DC,

6) It intersect BX at A,

7) now join AC,

Therefore ABC is the required Triangle.

Answer 2

Therefore $ABC$ is the required Triangle.

Step-by-step explanation:

Given;

$\bigtriangleup ABC$,$BC=4.2$ cm,$\angle B=30$ degree and $AB-AC=1.6$

we have to draw the Triangle ABC;

• We draw $BC=4.2$ cm as base of triangle

• At the point B , we draw a $30$ degree angle

• Let's cut the line segment $BD$ equal to $AB-AC=1.6$ cm, from the line BX

• Now we join $DC$

• Draw the perpendicular bisector $PQ$ of $DC$

• It intersect $BX$ at $A$

• Now join $AC$

Therefore $ABC$ is the required Triangle.