Construct triangle abc in which bc =5 cm angle b= 60 degree and ab +ac =7.5 cm
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Hey mate here is your answer
Answer:
Steps of Construction
STEP-1:- Draw a ray BX and cut off a line segment
BC =5cm from it
STEP-2:-Construct ∠XBY = 60°
STEP-3:- From BY cut off a line segment BD = 7.5 cm
STEP-4:- join cd
STEP-5:-raw the perpendicular bisector of CD, intersecting BY at a point A.
STEP-6:- join AC
Required ABC triangle is obtained.
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