Construct triangle ABC in which BC=5cm, Angle B=60° and AB+AC=10cm.
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Step-by-step explanation:
Draw the base BC and at the point, B makes an angle, say XBC equal to the given angle.
B]. Cut a line segment BD
equal to
AB+
AC
from the ray
BX.
C]. JoinDCand make an angle DCYequal toBDC.
D]. Let CY intersect BX at A
E]. ABC is the required triangle.
F]. In triangle ΔACD ,
∠ACD=
∠ADC
.
G]. So,
AB=
BD–AD=
BD–AC
H].
AB+
AC=
BD
From this we get,
BD=
14cm
.
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