Question

construct triangle ABC in which BC=6m B=60 AB-AC=2cm​

Answer 1

Step-by-step explanation:

. Draw a line BC=6cm

2. Construct 30

o

at B. Extend BP.

3. Take 3.1cm on compass, cut an arc on BP. Join CX.

4. Take perpendicular bisector of CX. It intersects with BP at A. Join AC

Answer 2

Step-by-step explanation:

Step first : Draw a line segment BC = 6 cm.

Step second : construct angle of 60° at B on BC.

Step third : Taking B as centre with 9 cm radius draw an arc which cut the ray of 60° angle at X

Step fourth : join X and c

Step fifth : the draw perpendicular bisector of XC

Step six: wherever this perpendicular bisector intersection BX, name that point as a A

Step seven: Join A and C

Step eight : so ∆ ABC will be the required triangle.

justification :-

AC = AX ( as point A on perpendicular bisector ramains equidistant from X and

AX + AB =9 cm

AC + AB = 9cm

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