construct triangle abc in which bc 8cm ab-ac=1 cm
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How to construct here...
Step-by-step explanation:
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hi bro...hope it helps you..good night..
Step-by-step explanation:
Step I: Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC. Step II: Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX. Step III: Join DC and draw the perpendicular bisector PQ of DC. Step IV: Let it intersect BX at point
Here is the diagram for you..
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