construct triangle ABC, in which side BC=7 cm, angle B=40° and AC-AB= 3
Answers
Answer:
solutions
Step-by-step explanation:
Solution : Let us draw a rought figure.
seg
BC = 7 cm. AC > AB.
We can draw ray BT such that
Z TBC = 40°
Point A is on ray BT. Take point D on
opposite ray of ray BT such that
BD = 3 cm.
Now AD = AB + BD = AB + 3 = AC
(:: AC – AB = 3 cm.)
.. AD= AC
.. point A is on the perpendicular
bisector of seg CD.
Construction of triangle ABC.
Step-by-step explanation:
This is a question that consists of the construction of a triangle.
Information we are provided with: BC=7 cm, ∠B=°, and AC-AB=3 cm
Step 1: Draw a 7-cm-long line segment BC.
Step 2: Draw a 45-degree angle from point B.
Step 3: Cut the line segment BD=1cm from Ray AX.
Step 4: Join C to D.
Step 5: Draw the DC's side bisector.
Step 6: At point A, the extended side bisector of DC intersects the Ray BX.
Step 7: Join A and C to form the needed triangle, ABC.
Hence, the triangle ABC is made. Refer to the figure for more information.