Question

construct triangle ABC such that AB=5.5cm, angle C=25° and the altitude from C to AB is 4 cm

Answer 1

Explanation mention below

Step-by-step explanation:

Step I: Draw a line segment AB = 5.5 cm.

Step II: Below AB, make  BAP =  CBA = 20  

Step III: Draw a line AE X AP at point A.

Step IV: Draw perpendicular bisector QR of AB. Suppose it meets AE at O and at AB at M.

Step V: With O as centre and OA as radius draw a circle.

Step VI: Take a point N on QR such that MN = 4.5 cm(altitude through C).

Step VII: Draw a line through N parallel to AB, intersecting the circle at C and C'.

Step VIII: Join AC, CB and C' A, C'B. Either of the triangles ABC, ABC’  is the required triangle.

To learn more

i)Construct a triangle abc such that ab=5.5cm,anglec=25°.and altitude from c to ab is 4cm

https://brainly.in/question/11893706

ii) Construct a ∆ABC in which AB = 6.5 cm, ∠B = 60° and BC = 5.5 cm. Also construct a triangle AB’C’ similar to ∆ABC, whose each side is 3 /2 times the corresponding sides of ∆ABC.

https://brainly.in/question/3121896

Answer 2

Given that,

Length of AB = 5.5 cm

Angle C = 25°

The altitude from C to AB is 4 cm.

Suppose, angle B = 60°

We know that,

Sum of angles of the triangle is equal to the  180°.

We need to calculate the third angle

Using sum of angles

$\angle A+\angle B+\angle C=180$

Put the value into the formula

$A+60+25=180$

$A=180-25-60$

$A=95^{\circ}$

We need to draw a triangle

Firstly, we draw a line segment AB = 5.5 cm

Now we draw a 4 cm line on AB from C

Now we draw a angle at A

$\angle BAC = 95^{\circ}$

Now we draw a angle at B

$\angle CBA = 60^{\circ}$

Now we draw a angle at C

$\angle ACB = 25^{\circ}$

Hence, This is required solution.