CONSTRUCT TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE
B = ^
CONSTRUCT THE PERPANDECULAR BISECTOR OF AB SUCH THAT IT CUTS AC. MEASURE THE LENGTH BS, SUCH THAT S IS THE POINT WHERE THE PERPENDICULAR BISECTOR AB CUTS AC
Answers
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Given : TRIANGLE ABC SUCH THAT AB = 9.8CM, BC = 6.5CM AND ABC = 88 DEGREE
To Find : Construct triangle ABC
Construct perpendicular bisector of AB , cut AC at S. Measure BS
Solution:
Step 1 : Draw a line segment BA = 9.8cm
Step 2 : draw an angle of 88° at B on BA using protractor
Step 3 : Using compass width = 6.5 cm and B as center , mark a point C on angle drawn in previous step
Step 4 : Join BC
Step 5 : Draw perpendicular bisector of AB cutting AC at S
Step 6 : Join BS
Step 7 : Measure BS = 5.9 cm
Perpendicular Bisector of AB
Step 1 : Use suitable compass width and taking A as center draw arcs on both sides
Step 2 : Keeping compass width same and taking A as center draw arcs on both sides such that it intersects arc drawn in previous steps at X and Y
Step 3: Join XY intersecting AB at M
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