Question

construct triangle ABC such that BC=3.2 cm , angle B = 45 and AC-AB = 2.1cm

Answer 1

• draw BC of 3.2 cm and at B draw an angle of 45 say angle-xbc.
• cut a line segment BS on the extension of the line bx below angle xbc of 2.1cm.
• join cs.
• draw the perpendicular bisector pq of cs.
• let it intersect bx at a point A.
• join CA.

Answer 2

Given:

We have given BC=3.2 cm , angle B = 45 and AC-AB = 2.1cm.

To Find:

We need to construct the triangle?

Step-by-step explanation:

• Since, We have given  BC=3.2 cm , angle B = 45 and AC-AB = 2.1cm.

• We will start with Draw a line segment BC=3.2cm

• At B, we will draw ,angleB 45 degree.

• From, BX,CUT OFF BD which is 2.1 in cm

• Join DC

• Now draw the perpendicular bisector LM of DC  which intersect BX at A.
• Now join AC.
• Then , we ABC is the required triangle.(see the diagram attach here)