Construct triangle DEF such that DE = 5 cm, DF=3 cm and m angle EDF =90°
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Answered by
1
Answer:
Draw a line segment DE of length 5 cm.
At D, draw a ray DX making 90° with DE.
With D as the center, draw an arc of radius 3cm to cut DX at point F.
Join EF to get the required triangle.
Thus, ΔDEF is the required triangle.
Step-by-step explanation:
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Answered by
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Step-by-step explanation:
To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90
o
.
Steps of construction:
(a) Draw a line segment DF=3cm
(b) At point D an angle of 90
o
with the help of compass i.e., ∠XDF=90
o
.
(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E
(d) Join EF
It is the required right angle triangle DEF
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