Question

Construct triangle pqr given pq=5cm, qr = 7cm,and angle q=60degrees for 7th class

Answer 1

step 1 : side QR of 7cm is drawn and centering of Q angle of 60° is drawn.

step2 : centering on Q arc of 5cm is drawn and name it P.

step 3 join all the points. this is our required triangle.

I hope it will help

don't forget to mark the answer as brainliests answer ❤❤❤

Answer 2

Solution:

To construct: A line, parallel to the given line by using ruler and compass.

Construction:

(i) Draw a line segment PQ and take a point R outside PQ.

(ii) Take any point X on PQ and join R to X.

(iii) With X as the center and take convenient radius, draw an arc cutting PQ at Y and RX at Z.

(iv) With R as center and the same radius as in step (iii), draw an arc AB cutting PX at O

(v) With the same arc YZ, draw the equal arc cutting AB at M.

(vi) Join MR to draw a line N.

This the required line PQ ǁ N