Question

construct triangle pqr if pq =7.5cm angle q=90*and pr-rq=4cm

Answer 1

rq= X
pr = 4+X
X^2+(7.5)^2= (X+4)^2
X=5.03125

Answer 2

pqr is a right triangle in which right angle is at q. So pq is the resultant vector which is equal to
pq=pr+rq
7.5=pr+rq
Adding above equation into pr-rq=4 we will get pr=5.75
Putting this value of pr in pr-rq=4
5.75-rq=4
rq=5.75-4
rq=1.75
By this we got all three sides of right triangle.