Question

construct triangle pqr in which or 6.5cm angle pqr=60 degree and pr - pq = 3cm​

Answer 1

Answer:

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Answer 2

Answer:

Here, PQ – PR = 2.5 cm ∴ PQ > PR As shown in the rough figure draw seg QR = 6.5 cm Draw a ray QT making on angle of 60° with QR Take a point S on ray QT, such that QS = 2.5 cm. Now, PQ – PS = QS [Q - S - T] ∴ PQ – PS = 2.5 cm ……(i) [Given] Also, PQ – PR = 2.5 cm …..(ii) [From (i) and (ii)] ∴ PQ – PS = PQ – PR ∴ PS = PR ∴ Point P is on the perpendicular bisector of seg RS ∴ Point P is the intersection of ray QT and the perpendicular bisector of seg RS Steps of construction: i. Draw seg QR of length 6.5 cm. ii. Draw ray QT, such that ∠RQT = 600. iii. Mark point S on ray QT such that l(QS) = 2.5 cm. iv. Join points S and R. v. Draw perpendicular bisector of seg SR intersecting ray QT. Name the point as P. vi. Join the points P and R. Hence, ∆PQR is the required triangle. Read more on Sarthaks.com - https://www.sarthaks.com/849767/construct-pqr-such-that-qr-6-5-cm-pqr-60-and-pq-pr-2-5-cm