Construct triangle PQR in which PQ + PR = 6.5 cm QR = 5.4 cm, ∠Q = 40°
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Step-by-step explanation:
Steps of construction of triangle PQR in which PQ + PR = 6.5 cm QR = 5.4 cm, ∠Q = 40° is as follows
- Draw a line segment QR=5.4 cm,then with the help of protector,draw 40° angle at Q,Extend that line up to X.
- Measure 6.5 cm with compass and draw an arc of 6.5cm on line QX.
- Join X to R.Draw a perpendicular bisector of line XR.
- The perpendicular bisector of XR on extension, meet QX at P.
- Join P and R.
Construction of ∆PQR has been done.
On measurements from constructed figure you will find that
PQ + PR = 6.5
which is required.
Hope it helps you.
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