Construct triangle PQR, in which Q = 70°, R = 80° and PQ+ QR+ PR = 9.5 cm.
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Draw a line segment AB (PQ+QR+PR=9.5 cm ) = 9.5cm.
2: Draw an angle of 70° at A and an angle of 80° at B.
3: Bisect ∠A and ∠B. Let the bisectors of ∠A and ∠B intersect in P.
4: Draw perpendicular bisector DE of AP which intersect AB in Q and FG of AB which intersect AB in R.
5: Join PQ and PR.
∴ ΔPQR is the required triangle
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