Question

Construct Triangle PQR in which QR=6cm angle Q = 45° PQ + PR = 10cm Write steps of construction.​

Answer 1

*Steps of Construction:

• Draw the base QR=6 cm.

• Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on opposite side of base QR.

• Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

• Let P be the intersection point of SX and perpendicular bisector AB.

Please see the attachment also.

$hope \: it \: helps \: you \: a \: lot.$