Question

construct triangle PQR in which QR=6cm , LR=75° and PQ+PR= 10.5cm​

Answer 1

Step-by-step explanation:

1.Draw base BC=7cm

2.Let's draw ∠B=75

∘

.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Join $$CD$

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:△ABC is the required triangle.