Question

Construct triangle pqr pq=5.5cm pq+qr=11cm angle p=70⁰

Answer 1

Answer:

Steps of Construction :

(i) Draw an equilateral ∆ RPQ in which PQ = QR = RP = 5.7 cm each.

(ii) From P and Q cut the bisector of ∠P and ∠Q, which intersect each other at point O.

(iii) With P as a centre draw an incircle which touches all the three sides of ∆RPQ.