Question

construct triangle PQR QR=3.8cm angle Q=45°, PQ+PR=6.8cm. justify your construction​

Answer 1

Answer:

Hope the answer which I uploaded may help you.

Answer 2

Constructed ∆PQR is attached.

Given:

• A ∆ PQR.
• QR=3.8cm angle Q=45°, PQ+PR=6.8cm.

To find:

• Construct and justify.

Solution:

Steps of construction:

1. Draw a line segment QR of 3.8 cm with the help of pencil and scale.
2. Draw $\angle XQR=45^{\circ}$ with the help of compass or protector.
3. Mark an arc of radius 6.8 cm on ray QX; the point is L.
4. Join L and R.
5. Draw perpendicular bisector of LR.
6. Mark the point P, where perpendicular bisector intersects the ray.
7. Join P and R.
8. Construction of ∆PQR is over.

Justification:

On measurement of sides of ∆PQR.

It is clear that

PQ= 3.8 cm

PR= 3 cm

Thus,

PQ+QR=6.8 cm

Hence verified.

Learn more:

1) Construct a triangle PQR in which QR = 4.6 cm, Q= 45° and PQ+PR = 8.2 cm.

https://brainly.in/question/49416835

2) Construct a Triangle ABC In which BC = 3.6 cm, AB + AC = 4.8 cm and angle B = 60 Degree

https://brainly.in/question/7051778