construct triangle pqr, qr =7cm L pqr =75 and pq+qr=9cm want full solution and diagram
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1.Draw base BC=7cm
2.Let's draw ∠B=75∘.Let the ray be BX
3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D
4.Join $$CD$
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:△ABC is the required triangle.
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