Question

Construct triangle PQR such that PQ=7 cm. QR=7 cm and <Q=70°​

Answer 1

Answer:

Step-by-step explanation:

Draw a line segment PQ of length 6 cm.

(ii) With P as centre, draw an arc of radius 4.5 cm.  

(iii) With Q as centre, draw an arc of radius 7 cm which intersects the previous arc at R.

(iv) Join PR and QR. Then ∆PQR is the required triangle....hope this helps u mark me brainliest