Question

construct triangle PQR such that QR =6.5cm , angle PQR = 40° and PQ - PR = 2.5 cm​

Answer 1

Step-by-step explanation:

step 1: construct a straight line QR =6.5 cm

step 2: At point Q construct an angle of 40°

step 3: on the arm of this angle mark point X at a distance of 2.5 cm from Q

step 4: join X to R

step 5: now the copy the angle formed at X on R

step 6: extend the arms of both the angles and mark their intersection as P