Construct triangle pqr such that QR is equal to 7.5 cm, pr - PQ is 1.3 cm and angle Q is equal to 40°
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Answer:
Please follow the following points:
Step-by-step explanation:
I hope this solution will help you-
1.Firstly, take base of 7.5cm and name it as QR.
2.Then,mark 40 degree angle from point Q and join the line.
3.Now, from point R, cut on the previous line an arc taking measurement 1.3 cm by a rounder.
4.The point where the segment joins is your point P.
5.Hence,your required triangle is constructed.
Sorry for no diagram.. :(
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