construct triangle pqr when pq= 4cm,pr=3cm and angle rpq=120 degree
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To construct: △PQR in which PQ=4cm,QR=3.5cm and PR=4cm
Steps of construction:
(a) Draw a line segment QR=3.5cm
(b) Taking Q as centre and radius 4cm, draw an arc.
(c) Similarly, taking R as centre and radius 4cm, draw an another arc which intersects first arc at P
(d) Join PQ and PR
It is required isosceles △PQR
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