Question

construct triangle PQR which qr=4.2cm <a=40 and pq+qr=8.5 ​

Answer 1

Step-by-step explanation:

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.

(2) Draw ray QT such that ∠RQT=40

(3) Mark point S on ray QT such that QS=8.5cm

(4) Draw seg RS.

(5) Construct the perpendicular bisector of seg RS.

(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

(7) Draw seg PR.Therefore, ΔABC is the required triangle.

I hope it can clear your doubt,

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