construct triangle XYZ in which angle Y =90degree , angle Z=30degree and perimeter is 13 cm. plz answer this question quickly in detail and please do this in notebook which help me alot Today is my paper
Answers
Answer:
Draw a line segment AB of 11 cm
Construct 30° from A and 90° from B
Construct angle bisectors for both the angles
They will meet at X
Draw perpendicular line bisector for AX and BX .
The both lines will meet AB at X and Y
Join XY and XZ
XYZ is our required triangle.
Step-by-step explanation:
The steps of construction to be followed:
Step 1: For given XY+YZ+ZX = 11 cm, a line segment PQ =11 cm is drawn.
Step 2: At points, P and Q angles of \angle RPQ = 30^{\circ} and \angle SQP =90^{\circ} are constructed respectively.
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Step 3: Now, bisects the angle RPQ and SQP. The bisectors of these angles intersect each other at a point X.
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Step 4: Construct the perpendicular bisector of PX and QX, name them as TU and WV respectively.
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Step 5: Let the bisector TU intersect PQ at Y and bisector WV intersect PQ at Z. Then XY and ZY are joined.
step aaa
Therefore, \triangle XYZ is the required triangle.