construct triangle xyz in which yz =6cm,xy+xz=9cm,angle xyz=50°
Answers
Step-by-step explanation:
As shown in the rough figure draw seg YZ = 6 cm Draw a ray YT making an angle of 50° with YZ Take a point W on ray YT, such that YW = 9 cm Now, YX + XW = YW [Y - X - W] ∴ YX + XW = 9 cm ….(i) Also, XY + XZ = 9 cm ….(ii) [Given] ∴ YX + XW = XY + XZ [From (i) and (ii) ] ∴ XW = XZ ∴ Point X is on the perpendicular bisector of seg WZ ∴ The point of intersection of ray YT and perpendicular bisector of seg WZ is j point X. Steps of construction: i. Draw seg YZ of length 6 cm. ii. Draw ray YT, such that ∠ZYT = 50°. iii. Mark point W on ray YT such that l(YW) = 9 cm. iv. Join points W and Z. v. Draw perpendicular bisector of seg WZ intersecting ray YT. Name the point as X. vi. Join the points X and Z. Hence, ∆XYZ is the required triangle.Read more on Sarthaks.com - https://www.sarthaks.com/849737/construct-xyz-in-which-yz-6-cm-xy-xz-9-cm-xyz-50