Question

construct triangles where AB =4.5cm, angle CAB =45°, angle CBA =75°

Answer 1

Answer:

This is the answer.......

Answer 2

Answer:

Btw, I'm Asian so my formula maybe different with what u have learned :0

Step-by-step explanation:

Consider

AB is c

Angle CAB is A

Angle CBA is B

AC is b

BC is a

Angle ACB is C

Apply this:

1. a²= b²+c²-2×b×c×cosA
2. b²= a²+c²-2×a×c×cosB
3. c²= b²+a²-2×a×b×cosC

Or this:

1. cosA= (b²+c²-a²)/2×b×c
2. cosB= (a²+c²-b²)/2×a×c
3. cosC= (a²+b²-c²)/2×a×b

Hope this will help u ;)