Question

Construct two tangents ab and ac from an external point a to a circle of radius 3.5cm and center o such that angle boc = 105 degree ​

Answer 1

Answer:

135°

Step-by-step explanation:

Steps of construction are as follows:-

1) Draw a circle of radius OQ= 3.5cm with centre at O.

2) Draw an angle of 90

0

from point O.

3) Let ray of angle intersect the circle at R.

4) Now draw 90°

from point Q

5) Draw 90°

at point R.

6) These two arcs meet each other, mark the point as P

PQ and PR are the two tangents inclined at angle of 45°

Now ∠AOB=90°

and ∠APB=45°

=∠AOB+∠APB=135°

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