Question

construct two tangents to a circle of radius 3.5cm from a point at a distance equal to its diameter​

Answer 1

As shown in figure $BP$ and $BQ$ are the required tangents where $BP=BQ$.

Step-by-step explanation:

Given,

Circle radius $3.5\ cm$ and construct two tangents equal distance from its diameter.

Following steps:

• Draw a line $OA=3.5\ cm$ using scale.
• $O$ as a center and $OA$ as radius draw a circle.
• Extend the line $OA$ like $OB$
• Bisect the line $OB$ where bisect line intersect the line $OB$ at $C$
• Take $C$ as center and $CB$ as radius draw another circle which intersect before circle at $P$ and $Q$
• Join $BP$ and $BQ$

Now, $BP$ and $BQ$ are the required tangents where $BP=BQ$.

Answer 2

BP and BQ are the required tangents where BP= BQ

Step-by-step explanation:

Given that

Circle radius 3.5 cm and construct two tangents equal distance from its diameter.

steps :

1. Draw a line  OA = 3.5 cm.
2. taking O  as a center and OA  as radius draw a circle.
3. Extend the line OA to OB .
4. Bisect the line OB   where bisect line intersect the line OB at C.
5. Take C as center and CB as radius draw another circle which intersect before circle at P and Q.
6. Join  BP and BQ.

BP and BQ are the required tangents where BP= BQ

#Learn more:

construct two tangents to a circle of radius 3.5cm from a point at a distance equal to its diameter​

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