Construct ∆ XYZ in which <Y = 70* , <Z = 60* , XY + YZ+ ZX = 11.6 CM
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Given xy+yz+zx=10cm,∠y=30
∘
,∠z=60
∘
Step 1 :- Draw a line segment AB
AB=xy+yz+zx
Step 2 :- make angle 30
∘
that is ∠y=30
∘
from point A.
Step 3 :- make angle ∠z=60
∘
from point B
Step 4 :- Draw bisector of ∠LAB & ∠MBA
these bisect at x.
Step 5 :- Draw ⊥er bisector from XA which intersect
AB at y.
Step 6 :- Draw ⊥er bisector from XB which is also
intersect AB at z.
Step 7 :- Join xy & xz.
∴△xyz is required and is formed.
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