Question

Construct ΔXYZ, in which YZ=6 cm, XY+XZ=9 cm. ∠XYZ = 50°

Answer 1

Step-by-step explanation:

To Construct ΔXYZ, in which YZ=6 cm, XY+XZ=9 cm. ∠XYZ = 50°,follow these simple steps of Construction

1. Draw a line segment YZ of 6cm.
2. Making Y as reference point draw an angle of 50°, with the help of protector.
3. Extend this line up to D,YD=9 cm
4. Join DZ.
5. Draw a perpendicular Bisector of DZ.
6. The perpendicular bisector intersect the line DY at X.
7. join XZ.

Construction of ∆XYZ has been over.

On measurement you get that XZ= 4.8 cm

and XY = 4.2 cm

XY+XZ=9 cm

Hope it helps you.

Answer 2

Step-by-step explanation:

Given :

=>  yz = 6

=>  x y + xz = 9 CM

=> ∠xyz = 50

Steps of Construction of triangle xyz:

=> Draw line segment of length 6cm and mark them yz.

=> Draw ray YV in such a way that ∠ZYV is equals to 50 degree.

=> Take point W on the rayYV in a such a way that YW = 9 cm.

=> Now, draw line segment WZ

=> Construct perpendicular bisector on the segment WZ.

=> Name the point  of intersection of ray  YW and the perpendicular bisector  of WZ as X

=> Draw line segment XZ

Thus, We get the required triangle XYZ as given in diagram.