construct ∆ xyz , where measure xyz=90° length (yz) =9cm , length (xz) =11cm • also bisect using compass and ruler
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(i) Draw a line segment which is sufficiently long using ruler.
(ii) Locate points X and Y on it such that XY=5cm.
(iii) At Y, construct a line segment YW, sufficiently large, such that ∠XYZ=100˚ ; use protractor to measure 100˚
(iv) With Y as centre and radius 5.5 cm, draw the line cutting YW at Z; join XZ.
⇒ Then XYZ is the required triangle.
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