Constructa ABC in which BC =4.2cm
B=120, AB=3.5cm draw AD BC.
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Answer:
BC = 4.2cm, ∠ABC = 60˚ and AB = 5 cm
Steps of construction :
(i) Draw BC of length 4.2 cm
(ii) Draw an angle of 60˚ at B.
(iii) Cut BA = 5 cm and join A to B.
(iv) Draw angle bisector of ∠ABC.
(v) Draw BD at 2 cm intersecting EF at O.
(vi) Taking O as centre and 2 cm as radius draw the required circle.
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