Question

Constructe a quadrilateral ABCD in which AB=6cm, BC=5cm,angle A=55°, angle B=110° and angle D=90° .

Answer 1

"Given: AB = 6 cm, BC = 5cm, angle A = 55 degree, angle B = 110 degree and angle D = 90 degree.

Steps;

Angle sum property of a quadrilateral:

∠A + ∠B + ∠C + ∠D = 360 degree

55 + 110 + ∠C + 90 = 360 degree

∠C = 105 degree

1. Draw AB = 6 cm.

2. Take A as a centre construct an angle of 55 degrees and then from B make 110 degrees.

3. Take the measurement of BC = 5cm on the compass and cut the angle 110 line. Mark the point as C.

4. Now take C as a centre and construct 105 degrees.

5. The point where angle C and D will meet will be D.

"

Answer 2

Answer:

here is your answer

hope it helps

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Explanation:

as angle a ,angle b and angle d are given 55,110,90 degrees respectively . we need to find the fourth angle by angle sum property that is 55+110+90+x=360.

then you will find 105+x= 360 .

then x=105 degree . so angle c is 105 degree.