Math, asked by indrajk12345678, 10 months ago

Construction : a, b, c are three non collinear points such tha distance between a and b is 7 cm and distance between b and c is 6 cm and distance between a and c is 7 cm. Draw a circle passing through all three points and draw a circle with radius 2 cm touching the circle internally at point a



Answers

Answered by alisalimali78666
1

Step-by-step explanation:

First draw ab of length =7cm

then TAKE b as centre and make an arc with 6 cm as radius...

now take A as centre and 7cm radius draw another arc intersecting the previous arc now name this point of intersection as c

now draw perpendicular bisectors of ab and bc and taking this point of intersection of these bisectors as centre and the perpendicular distance as radius draw a circle which will pass through all the points.

PERPENDICULAR BISECTORS:

For a given line segment say AB take more than half of its length as radius and draw arcs from both the ends on either sides of AB then join the point of intersections this will give u perpendicular bisector....

Answered by AditiHegde
1

Construction : a, b, c are three non collinear points such tha distance between a and b is 7 cm and distance between b and c is 6 cm and distance between a and c is 7 cm. Draw a circle passing through all three points and draw a circle with radius 2 cm touching the circle internally at point a

 Steps of construction:

1. Draw a line BC with a scale of 6 cm.

2. From point B with a measure of 7 cm draw an arc above the line BC.

3. From point C with a measure of 7 cm draw an arc above the line BC.

4. A point where these arcs meet mark it as A.

5. Join BA and CA.

6. Hence the required triangle.

7. With a scale of more than half the measure of line AB draw arcs from points  A and B above and below the line AB.

8. Join the points where theses arcs meet.

9. With a scale of more than half the measure of line BC draw arcs from points  B and C above and below the line BC.

8. Join the points where theses arcs meet.

7. With a scale of more than half the measure of line AC draw arcs from points  A and C above and below the line AC.

8. Join the points where theses arcs meet.

9. We get a point "O" where all the above lines meet.

10. Hence is the center of the required circle.

11. Draw a circle with center "O" passing through points A, B and C.

12. With a radius of 2 cm draw a circle at point A.

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